14m^2-2=0

Solution for 14m^2-2=0 equation:

14m^2-2=0

a = 14; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·14·(-2)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{7}}{2*14}=\frac{0-4\sqrt{7}}{28}
=-\frac{4\sqrt{7}}{28}
=-\frac{\sqrt{7}}{7}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{7}}{2*14}=\frac{0+4\sqrt{7}}{28}
=\frac{4\sqrt{7}}{28}
=\frac{\sqrt{7}}{7}
$